Based on detailed analysis of last 5 years' papers. Perfect for 2026 Boards prep!
| Question Example | Type/Marks | Years Repeated | Notes |
|---|---|---|---|
| Find intervals where f(x) = x³ - 3x² + 3x + 2 (or similar cubic) is increasing or decreasing. Use first derivative test. | Short Answer (3 marks) | 2021, 2022, 2023, 2024, 2025 | Repeated 5x; f'(x) = 3(x-1)² ≥ 0 → increasing everywhere; critical point x=1 (point of inflection). |
| Find local maxima and minima of f(x) = x³ - 3x + 2 (or -x³ + 3x - 2). Use second derivative test. Also find absolute max/min in [a,b]. | Long Answer (4-5 marks) | 2021 Term 2, 2022, 2023, 2024 | Repeated 4x; Critical points x=±1; f''(x)=6x → max at x=-1, min at x=1. |
| Find the approximate value of √26 or (1.01)^5 or cos(59°) using differentials (linear approximation). | Short Answer (2-3 marks) | 2022, 2023, 2024, 2025 | Repeated 4x; dy ≈ f'(x)dx; e.g., √26 ≈ 5.099 using x=25, dx=1. |
| Assertion: If f'(x) > 0 in an interval, then f is strictly increasing. Reason: By definition of derivative and mean value theorem. | Assertion-Reason (1 mark) | 2023, 2024, 2025 | Repeated 3x; Both true, reason explains. |
| Find equation of tangent and normal to y = x³ - 3x + 1 at x=1 (or at point where slope is given). | Short Answer (3 marks) | 2021 Term 1, 2022, 2023, 2025 | Repeated 4x; Slope = dy/dx at point; tangent: y - y1 = m(x - x1); normal perpendicular. |
| An open box is to be made from a square sheet of side 12 cm by cutting equal squares from corners. Find side of square cut so volume is maximum. | Long Answer (4-6 marks) | 2022, 2023, 2024, 2025 | Repeated 4x; V = x(12-2x)²; max at x=2 cm (second derivative test or sign chart). |
| MCQ: The function f(x) = x² - 4x + 5 has minimum value at x= ? (a) 1 (b) 2 (c) 3 (d) 4 | MCQ (1 mark) | 2021 Term 1, 2023, 2024 | Repeated 3x; Answer (b) 2 (vertex form or f'=0). |
| A spherical balloon is being inflated at 10 cm³/s. Find rate of increase of radius when r=5 cm. | Short Answer (3 marks) | 2023, 2024 | Repeated 2x; V=4/3 π r³ → dr/dt = (dV/dt)/(4π r²) = 10/(4π×25). |
| Case-based: Given cost/revenue function or geometric figure, find maximum profit/area or minimum cost using derivative. | Case-Based (4-6 marks) | 2023, 2025 | Repeated 2x; Set derivative=0, check second derivative or sign change. |
| Show that the rectangle of maximum area inscribed in a circle of radius r has diagonal equal to diameter (or sides √2 r). | Proof/Short Answer (3 marks) | 2021 Term 2, 2024 | Repeated 2x; A = x √(4r² - x²); max when x = r√2. |
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